Question

Find the area of triangle both side 18cm, 10cm ,14 cm

Answer 1

$\huge\underline{\mathbb\red{✰g}\green{i}\mathbb\blue{v}\purple{e}\mathbb\orange{n}\pink{,}}\:$,

➠a = 18cm

➠b = 10cm

➠c = 14cm

so,

s= $\frac{a+b+c}{2}$,

= $\frac{18+10+14}{2}$,

=. $\frac{42}{2}$,

=. 21

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$\huge\underline{\mathbb\red{✰s}\green{o}\mathbb\blue{l}\purple{u}\mathbb\orange{ti}\pink{on}}\:$,

$\area of ∆{=\: s(s-a)\:(s-b)\:(s-c)}$

➣$\sqrt{s(s-a)(s-b)(s-c)}$

➠ $\sqrt{21(21-18)(21-10)(21-14)}$

➠$\sqrt{21×3×11×7}$

➠ $\sqrt{7×3×3×11×7}$

➠7×3 $\sqrt{11}$

➠21$\sqrt{11}$cm..answer