Question

Find the area of triangle by heron's formula whose sides are 18,34and30

Answer 1

Answer:

Area = 269.46

Step-by-step explanation:

In Herons formula we have AREA =       $\sqrt{S(S-A)(S-B)(S-C)}$

Where    A , B , C are Side of traingle

and     S = ( A + B + C ) / 2

                     First we will find the value of S

                        so     S = ( 18 + 34 + 30 ) / 24

                                     = 41

now put the values of S ,A ,B and C we have

                   Area of Traingle = $\sqrt{S(S-A)(S-B)(S-C)}$

                                                 = $\sqrt{41(41-18)(41-34)(41-30)}$

      calculating we will get    area  = $\sqrt{72611}$

                                                          = 269.46

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