Question

find the area of triangle by herons formula with side 26,30and40cm

Answer 1

a=26cm
b=30cm
c=40cm
s=26+30+40/2=96/2=48
Area=√48(48-26)(48-30)(48-40)
=√48x22x18x8
=√3x4x4x11x2x9x2x4x2
=4x2x2x3√11x2x3
=48√66cm^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=389.95\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =26 cm,30 cm,40 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{26+30+ 40}{2} \\ \\ : \implies s = \frac{96}{2} \\ \\ \green{ : \implies s =48 } \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{48(48- 26)(48-30)(48- 40)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{48\times 22\times 18\times 8} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{152064} \\ \\ : \implies \text{Area \: of \: triangle =}389.95\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle = 389.95\: {cm}}^{2} }$