Question

Find the area of triangle formed by joining the mid point of the sides of triangle whose verticals are A(2,3)B(4,4)andC(2,5)

Answer 1

Step-by-step explanation:

• Given points

A(2,3) ,B(4,4) ,C(2,5)

So,Area of triangle is given by -

$\frac{1}{2} |x ^{1} (y ^{2} - y ^{3} ) + x ^{2} (y ^{3} - y ^{1} + x ^{3} (y ^{1} - y ^{2}) |$

Area is :-

$\frac{1}{2} |2(4 - 5) + 4(5 - 3) + 2(3 - 2)|$

$\frac{1}{2} |2 \times - 1 + 4 \times 2 + 2 \times 1|$

$\frac{1}{2} | - 2 + 8 + 2|$

$\frac{1}{2} |8|$

$4u ^{2}$

Area is 4u²