Question

Find the area of triangle formed by points A(6,0) and B(0,8) and origin....

Please answer fast it's very urgent..... ​

Answer 1

$Given \: the \:points \: A(6,0) , \: B(0,8) \:which$

$form\: a \: triangle \:with \:Origin \: O(0,0)$

$\triangle AOB \: is \: right \: angle \: triangle$

$and \: the \:base \: is \: 6 \: units$

$\blue{ (x \: Coordinate \: of \: point \:A )}$

$Height \: is \: 8 \:units$

$\blue{ (y \: Coordinate \: of \: point \:B)}$

$\therefore \red{Area \:of \:\triangle= \frac{1}{2} \times base \times height}$

$= \frac{1}{2} \times 6 \times 8$

$= 3 \times 8$

$= 24 \: square \:units$

Therefore.,

$\red{Area \:of \:\triangle}\green { = 24 \: square \:units}$

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