Question

find the area of triangle formed by the following st.lines and the coordinates arxes. 3x-4y+12=0​

Answer 1

Answer:

Given the equation of the straight line is 3x+4y=12.

This straight line can be written as in the intercept form as,  

4

x

​

+  

3

y

​

=1

From the intercept form of the given line, it can be concluded that the line intersects the co-ordinate axes at the points (4,0) and (0,3).

Now we get a triangle whose base is of length 4 units and length of perpendicular of length 3 units.

So, the area of the triangle will be,

⇒  

2

1

​

×3×4

⇒6 sq. units

Step-by-step explanation:

hope its helpful

sam❤❤❤