find the area of triangle formed by the line 2x+3y=12 and the coordinate axis
Answers
Answered by
17
put X=0
then y=4
put y=0
then X=6
hence y intercept is 4 and X intercept is 6
area=1/2 *base *height
area=1/2 *6*4
area=12
then y=4
put y=0
then X=6
hence y intercept is 4 and X intercept is 6
area=1/2 *base *height
area=1/2 *6*4
area=12
Answered by
7
Given:
The triangle formed by the line 2x+3y=12 and the coordinate axis
To Find:
The Area of the triangle.
Solution:
We have the line equation 2x + 3y = 12 .
We can convert it into intercept form to get coordinates of its intersection with the coordinate axis.
- 2x + 3y = 12
- In intercept form,
- x/6 + y/4 = 1
Therefore
- x intercept = (6,0)
- y intercept = (0,4)
Therefore the area of triangle,
- A = 0.5 x X intercept x Y intercept
- A = 0.5 x 6 x 4
- A = 12 sq units.
The area of triangle formed by the line 2x+3y=12 and the coordinate axis is 12 sq units.
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