Math, asked by Abaan3419, 11 months ago

Find the area of triangle formed by the line joining the points (1,7), (2,-5) with co ordinate axes

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Answered by 24921
12

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Answered by gayatrikumari99sl
2

Answer:

15 .041 square units is the required area .

Step-by-step explanation:

Explanation:

Given , the line joining the points  are (1 , 7) and  (2 , -5) .

Let   the points A (1 , 7 ) and B(2 , -5 )

Equation of line passing through point (x_1, y_1) and (x_2 , y_2) is

y - y_1 = \frac{y_2 - y_1}{x_2 - x_1}  (x- x_1)

Step 1:

Two points are , A(1, 7 ) and B(2 , -5).

x_1 = 1 , y_1 = 7 , x_2 = 2 and y_2 = -5

So the equation of line passing through the point A(1,7) and (2 ,-5) is

y - 7 = \frac{-5  - 7}{2  - 1 }  (x- 1 )

⇒y - 7 = -12 (x - 1)  ⇒ y - 7 = -12x + 12

⇒ 12x + y = 12 + 7 = 19

⇒12 x + y = 19

Divide both side by 19 we get ,

\frac{12x}{19}  + \frac{y}{19} = \frac{19}{19}

\frac{12x}{19}  + \frac{y}{19} =  1 , this satisfy the equation \frac{x}{a} + \frac{y}{b}   = 1

Therefore , x intercept is a=  \frac{19}{12}   and  y intercept is  b = 19.

In ΔPOQ  , OQ  is base  = \frac{19}{12} and OP is height  = 19 .

Area of triangle = \frac{1}{2} × base × height .

⇒ Area = \frac{1}{2} × \frac{19}{12}× 19

⇒ Area = \frac{361}{24} =  15 .041 square units .

Final answer:

Hence , the area  of triangle  is  15 .041 square units .

#SPJ3

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