find the area of triangle formed by the lines 3x+y-2=0,5x+2y-3=0,2x-y-3=0
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Answer:
Area = 0
Step-by-step explanation:
3x+y-2=0 Eq1
5x+2y-3=0 Eq2
2x-y-3=0 Eq3
2*Eq1 - Eq2
=> x - 1 = 0
=> x = 1 & y = -1
Eq1 + Eq 3
5x - 5 = 0
=> x = 1 & y = - 1
Eq2 + 2* eq3
9x - 9 = 0
=> x = 1 & y = -1
Hence all the lines intersects at same point
so Area = 0
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