Question

Find the area of triangle formed by the lines y = 3x + 2, y = -5x – 3 and
x = 0. Also find the altitude of the triangle to the base x = 0.

Answer 1

Answer:

Given the equation of the straight line is 3x+4y=12.

This straight line can be written as

4

x

+

3

y

=1......(1).

From (1) we have the line intersect the co-ordinate axes at the points (4,0) and (0,3).

Now we get a triangle whose base is of length 4 units and length of perpendicular of length 3 units.

So the area of the triangle will be

2

1

×3×4=6 sq units.