find the area of triangle formed by the point (2,3)
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6
Answer:
ANSWER
Δ=
2
1
[−2(−5−y)+4(y−3)−3(3+5)]
=
2
1
(10+2y+4y−12−24)
=
2
1
(6y−26)=3y−13
∴3y−13=10 or y=
3
23
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