find the area of triangle formed by the points (1,3)(-7,6)(5,-1)
Answers
Answered by
0
Area = 1/2 | x1(y2-y3) + x2(y3-y1) +x3(y1-y2) |
= 1/2 | 1(7) - 7 (-4) + 5(-3) | = 1/2 | 7+28-15| = 20/2 = 10 sq.units
= 1/2 | 1(7) - 7 (-4) + 5(-3) | = 1/2 | 7+28-15| = 20/2 = 10 sq.units
Anonymous:
wrong....
7 + 28 - 15 = 20
is it ok now?
please mark as brainliest
yaa good
Answered by
4
Hey friend...!! here's your answer
__________________________
Area of triangle ==>
1/2 [ x1 (y2 - y3) + x2 (y3-y1) + x3 (y1 - y2) ]
=1\2 [ 1(6 - (-1) + (-7)(-1-3) + 5(3-6) ]
=1/2 [ 7 + 28 -15 ]
=1/2 [20]
=10 sq. unit..
so that the area of triangle is 10 sq. unit.
____________________________
#hope its help you dear#
☺
__________________________
Area of triangle ==>
1/2 [ x1 (y2 - y3) + x2 (y3-y1) + x3 (y1 - y2) ]
=1\2 [ 1(6 - (-1) + (-7)(-1-3) + 5(3-6) ]
=1/2 [ 7 + 28 -15 ]
=1/2 [20]
=10 sq. unit..
so that the area of triangle is 10 sq. unit.
____________________________
#hope its help you dear#
☺
pllss
mark as brainlist
if its help
Similar questions