Question

find the area of triangle formed by the points (2,3) (-1,0) (2,-4)​

Answer 1

Let A=(2,3) , B=(-1,0) , c =(2,-4)

$AB = \sqrt{(2 + 1)^{2} +(3 - 0)^{2}}$

$\sqrt{9 + 9}$

$\sqrt{18}$

$3 \sqrt{2}$

$BC = \sqrt{(2 + 1)^{2}( - 4 - 0) ^{2} }$

$\sqrt{9 + 16}$

$\sqrt{25}$

$5$

$CA = \sqrt{(2 - 2)^{2}+(3+4)^{2}}$

$\sqrt{0 + 49}$

$\sqrt{49}$

$7$

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