find the area of triangle formed by the points (4, 3)and (5, 4) and (11, 2)
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Answers
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Answer:
It is 4 sq units
Step-by-step explanation:
Hi viewer,
we are given 3 points A(4,3),B(5,4) and C(11,2)
ar of triangle
= 1/2 | x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
=1/2 | 4(4-2)+5(2-3)+11(3-4)|
=1/2 | 4 (2) + 5(-1)+11(-1)|
=1/2 | 8-5-11|
=1/2 | -8 |
=1/2×8
=4 square units
Hence the area of triangle is 4 sq units
hope it helps!!
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