Question

FIND THE AREA OF TRIANGLE HAVING PERIMETER 32CM. ONE SIDE OF ITS SIDE IS EQUAL TO 11CM AND DIFFERENCE OF THE OTHER TWO IS 5CM.

PLS ANSWER FAST ITS URGENT...!!!​

Answer 1

Step-by-step explanation:

let the others two sides are x and y

so x-y=5

now x=5+y

if y=8 then x will be 13 and there for 13+8+11=32

so area of triangle will be equal to squareroot of s(s-a)(s-b)(s-c)

=sqrt32(32-13)(32-8)(32-11)

=sqrt32(19)(24)(21)

=sqrt306432

=554 square unit