Question

find the area of triangle having sides 41cm,15cm and 28cm​

Answer 1

Answer:

Area is 126 sq.cm

Step-by-step explanation:

all sides of ∆ is different so it is heterogeneous ∆.

Area of ∆=√s(s-a)(s-b)(s-c)

s= perimeter/2 = (41+28+15)/2 =42

a=41, b=28 & c=15

Area of triangle = √{42×(42-41)×(42-28)×(42-15)}

Area of ∆ = √( 42 ×1 ×14 ×27)

Area =126 sq.cm

Answer 2

Answer:

126 cm.square

Step-by-step explanation:

Using heron's formula

√s(s-a) ×(s-b)×(s-c)

s= a+b+c ÷ 2 = (41+28+15)÷2= 42

√42×(42-41)×(42-28)×(42-15)

√42×1×14×27=126 cm.square

Hope it helps you