find the area of triangle if its sides are÷ 3,3,3
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Given triangle sides are 3,3,3
All the sides are equal
So , it is an equilateral triangle
Let the side =a
Area = (root 3)a^2/4
=(root 3)*(3^2)/4
=(9 root3)/4 squre units
All the sides are equal
So , it is an equilateral triangle
Let the side =a
Area = (root 3)a^2/4
=(root 3)*(3^2)/4
=(9 root3)/4 squre units
Answered by
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Given that :-
All three sides of triangle are equal i.e 3,3,3 so it is an equilateral triangle.
Assume the side of triangle = "s"
So for an equilateral triangle -
Area = √3/4(s²)
⇒Area = √3/4 (3²)
=√3/4 (9)
=9√3/4 sq. units
Or
=3.90 sq. units
----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
All three sides of triangle are equal i.e 3,3,3 so it is an equilateral triangle.
Assume the side of triangle = "s"
So for an equilateral triangle -
Area = √3/4(s²)
⇒Area = √3/4 (3²)
=√3/4 (9)
=9√3/4 sq. units
Or
=3.90 sq. units
----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
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