find the area of triangle if sides are 42 cm ,39 cm,45 cm
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Hi ,
Let a = 42cm , b = 39 cm , c = 45cm
are three sides of a Triangle.
s = ( a + b + c ) /2
= ( 42 + 39 + 45 ) /2
= 126/2
= 63
s - a = 63 - 42 = 21
s - b = 63 - 39 = 24
s - c = 63 - 45 = 18
Therefore ,
By Heron's formula ,
Area of the triangle ,
∆ = √ s( s - a ) ( s - b ) ( s - c )
= √ 63 × 21 × 24 × 18
= √ 9 × 7 × 7 × 3 × 2 × 2 × 6 × 6 × 3
= √ ( 3×3×3×3)×(7×7)×(6×6)×(2×2)
= 3 × 3 × 7 × 6 × 2
= 756 cm²
I hope this helps you.
:)
Let a = 42cm , b = 39 cm , c = 45cm
are three sides of a Triangle.
s = ( a + b + c ) /2
= ( 42 + 39 + 45 ) /2
= 126/2
= 63
s - a = 63 - 42 = 21
s - b = 63 - 39 = 24
s - c = 63 - 45 = 18
Therefore ,
By Heron's formula ,
Area of the triangle ,
∆ = √ s( s - a ) ( s - b ) ( s - c )
= √ 63 × 21 × 24 × 18
= √ 9 × 7 × 7 × 3 × 2 × 2 × 6 × 6 × 3
= √ ( 3×3×3×3)×(7×7)×(6×6)×(2×2)
= 3 × 3 × 7 × 6 × 2
= 756 cm²
I hope this helps you.
:)
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