Find the area of triangle in which:
1) The right angled triangle in which hypotnuese is 13 cm and one side is 5cm ..
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Let the one side be AB, so that
Using Pythagoras Theorem, we get
AB^2 + BC^2 = AC^2
or, AB^2 = 13^2 - 5^2
or, AB^2 = 169 - 25 = 144
or, AB = √144 = 12 cm
Semi-perimeter = 13 + 12 + 5 / 2 = 30/2 = 15 cm
Heron's Formula = √s(s-a)(s-b)(s-c)
Heron's Formula = √15(15-13)(15-12)(15-5)
Heron's Formula = √15 × 2 × 3 × 10
Heron's Formula = √3 × 5 × 2 × 3 × 2 × 5
Heron's Formula = 3 × 2 × 5
Area of the Triangle = 30 sq.cm
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