Question

find the area of triangle in which a=5 b= 12 c=13

Answer 1

heyyyyyyyyyyyyy friendddddddddd...

Here's your answer...

Its done below.....

Given,
a= 5
b= 12
c= 13

semi perimeter=a+b+c/2
=5+12+13/2
=15

therefore,area of the triangle=√s(s-a)(s-b)(s-c)
=√ 15×10×3×2
=√3×5×2×5×3×2
=√3^2 × 5^2 × 2^2
=3×5×2
=30

area of the triangle =30

HOPE IT HELPS YOU

Answer 2

There are multiple ways in which you can find the area of a triangle 
One of the basic ways by which I'm going to do this question is '"Heron's
Formula"


Sol:-  Acc. to Heron's formula,
                                    First, we need to find the value of semi-perimeter of the given triangle, which is given as
                                             semi-perimeter = (a+b+c)/2
                                                                         = (5+12+13)/2
                                                                          =30/2
                                                                           =15

Now, Area of triangle = √p(p-a)(p-b)(p-c),                 where p=semi-perimeter
                                     = √15(15-5)(15-12)(15-13)
                                     = √15(10)(3)(2)
                                     = √900
                                     = 30