Question

find the area of triangle in which: (a) a=13m, b= 14m, c=15m

Answer 1

The area of triangle is 84 sq.m.

Step-by-step explanation:

Sides of triangle :

a=13 m

b = 14 m

c = 15 m

Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

Where $s=\frac{a+b+c}{2}$

Substitute the values:

$s=\frac{13+14+15}{2}=21$

Area =$\sqrt{21(21-13)(21-14)(21-15)} = 84 sq.m .$

#Learn more:

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Answer 2

Question

Find the area of triangle in which . a=13m,b=14m, c=15m.

Answer

${84m}^{2}$

$</h3><h3></h3><h3>= \frac{a + b + c}{2} \\ \\ s = \frac{13 + 14 + 15}{2} \\ \\ s = \frac{42}{2} \\ \\ s = 21m$

Note

where a,b,and C are the sides of the given triangle and s is its Semi - perimeter (s),

Here we using Heron's Formula

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{21(21 - 13)(21 - 14)(21 - 15)} \\ \\ \sqrt{21(8)(7)(6)} \\ \\ \sqrt{7056} \\ \\ \sqrt{84 \times 84} \\ \\ {84m}^{2}$

Therefore the area of triangle is ${84m}^{2} .$

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