find the area of triangle in which the first side is 25 CM second 60 cm and third is 65 CM
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Hii Friend,
∆ABC is an isosceles triangle . In which,
AB = 25 CM , BC = 60 CM And AC = 65 CM.
Semi perimeter ( S) = 1/2( AB +BC + AC ) = 1/2 ( 25 + 60 + 65) = 1/2 × 150 = 75 CM.
S - AB = 75 - 25 = 50 CM
S - BC = 75 - 60 = 15 CM
S - AC = 75 - 65 = 10 CM.
Therefore,
Area of the ∆ ABC = ✓ S(S-AB)(S-BC)(S-AC) = ✓75 × 50 × 15 × 10 = ✓562502 = 750 CM².
Hence,
The area of isosceles ∆ABC = 750 CM².
HOPE IT WILL HELP YOU..... :-)
∆ABC is an isosceles triangle . In which,
AB = 25 CM , BC = 60 CM And AC = 65 CM.
Semi perimeter ( S) = 1/2( AB +BC + AC ) = 1/2 ( 25 + 60 + 65) = 1/2 × 150 = 75 CM.
S - AB = 75 - 25 = 50 CM
S - BC = 75 - 60 = 15 CM
S - AC = 75 - 65 = 10 CM.
Therefore,
Area of the ∆ ABC = ✓ S(S-AB)(S-BC)(S-AC) = ✓75 × 50 × 15 × 10 = ✓562502 = 750 CM².
Hence,
The area of isosceles ∆ABC = 750 CM².
HOPE IT WILL HELP YOU..... :-)
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