find the area of triangle in which two sides are 8cm, 11cm and it's perimeter is 32cm
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Question :-
⤏ find the area of triangle in which two sides are 8cm, 11cm and it's perimeter is 32cm.
Given that :-
⤍ a = 8cm
⤍ b = 11cm
⤍ c = ?
To find :-
⤏ Area of triangle
Solution :-
⤏ a + b + c = 32
⤏ 8 + 11 + c = 32
⤏ 19 + c = 32
⤏ c = 32 – 19
⤏ c = 13cm
⤏ s = a + b + c/2
⤏ 32/2
⤏ 16cm
By herons formula :-
⤏ Area of ∆ = √s (s – a) (s – b) (s – c)
⤏ √16 (16 – 8) (16 – 11) (16 – 13)
⤏ √16 × 8 × 5 × 3
⤏ 4 × 4 × 2 × 2 × 5 × 3
⤏ 4 × 2 √2 × 5 × 3
⤏ 8√30 cm² answer.
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