Question

find the area of triangle joining the midpoint of the sides of a triangle whose vertisis is A(2,3) B(4,4) C(2,6)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

1/2(x1(y1-y2)+x2(y2-y3)+x3(y1-y2) ))

Step-by-step explanation:

1/2(2(6-4)+4(4-6)+2(3-4)

1/2(2(2)+4(-2)+2(-1))

1/2(4-8-2)

1/2(4-10)

1/2(-6)

$||$

1/2*6 (since from mode it came out so +)

=3