Question

Find the area of triangle PQR in which angle PQR= 120⁰, PQ=7cm and QR= 6cm.
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Answer 1

Step-by-step explanation:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.

Therefore, PQRS is the required quadrilateral

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Answer 2

Answer:

21cm^2

Base =6cm

Height = 7cm

Step-by-step explanation:

area of triangle = _1_ × base ×height

2

area of triangle=_1_ × 6 ×7

2

area of triangle = 21sq cm