Question

Find the area of triangle pqr such that angle q = 90° ,pr = 10 cm and angle prq =30°

Answer 1

Step-by-step explanation:

sinR = PQ/PR

sin30°=PQ/10

1/2 = PQ/10

PQ = 5

cosR = QR/PQ

cos30° = QR/10

√3/2 = QR/10

QR = (10√3)/2

QR = 5√3

Area = 0.5*QR*PQ

= 0.5*5√3*5

= (25√3)/2