Question

Find the area of triangle
PR= 20cm, QR=21cm and PQ=?

Answer 1

Answer:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse) 2

=(Base) 2+(Perpendicular) 2

[By Pythagoras theorem]

⇒(QR) 2 =(PQ) 2 +(PR) 2

⇒x 2 =(10) 2 +(24) 2

⇒x 2 =100+576=676

⇒x= 676 =26cm

Thus, the length of QR is 26cm.

Step-by-step explanation:

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Answer 2

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