Question

find the area of triangle sides are 122cm,22cm,120cm​

Answer 1

Step-by-step explanation:

solve by formula √s(s-a)(s-b)(s-c)

s=a+b+c/2

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Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

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$\bold{\huge{\underline{\underline{\rm{ Given :}}}}}$

Sides -

a = 122 cm

cm b = 22 cm

cm c = 120 cm

$\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}$

Area of Triangle .

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The herons formula to find Area of Triangle is :

$area(a) = \sqrt{p(p - a)(p - b)(p - c)}$

Where P is half perimeter.

$p = \frac{a + b + c}{2}$

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$\purple{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

First find out the value of P →

$p = \frac{122 + 22+120}{2} \\ p = \frac{264}{2}$

$p = 132$

Now Area is ,

$a = \sqrt{132(132-122)(132-22)(132-120)} \\ a = \sqrt{132 \times 10 \times 110 \times 12}$

$a = \sqrt{1,742,400}$

$\boxed{a = 1,320}$

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