Question

find the area of triangle sides are 60, 153,and 111

Answer 1

Given: The sides of a triangle are 60cm, 153cm and 11cm.

To find: The area of the triangle.

Answer:

Heron's formula: √s(s - a)(s - b)(s - c)

Let a be 60cm, b be 153cm and c be 111cm.

a + b + c = Perimeter

60 + 153 + 111 = 324cm

a + b + c/2 = Semi - Perimeter (s)

324/2 = 162cm

s - a = 162 - 60 = 102cm

s - b = 162 - 153 = 9cm

s - c = 162 - 111 = 51cm

Area of a triangle = √s(s - a)(s - b)(s - c)

= √162*102*9*51

= √2*3*3*3*3*2*3*17*3*3*3*17

= 2*3*3*3*3*17

= 2754cm^2

Hope it helps :)

Answer 2

Hey dear here is your answer!!!!!

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We have been given the sides of the triangle as 60, 153 and 111 units.

We know that the area of a triangle is - $\sqrt{s(s-a)(s-b)(s-c)}$, where a,b and c are the sides of the triangle.

The semi perimeter of the triangle would be:-

= $\frac{60+153+111}{2}$

= $\frac{324}{2}$

= 162 units

Substitute the value of 's' in the formula:-

= $\sqrt{162(162-60)(162-153)(162-111)}$

= $\sqrt{162(102)(9)(51)}$

Factorize the numbers:-

= √ 2 x 3 x 3 x 3 x 3 x 2 x 3 x 17 x 3 x 3 x 3 x 17

= 2 x 3 x 3 x 3 x 3 x 17

= 2754 units²

So, 2754 units² is your answer !

$\large\boxed{\large\boxed{\large\boxed{Solved !}}}}$

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️