Question

find the area of triangle the point is

A=(a,a)
B=(-a,-a)
C=(-√3a,√3)

By using of area of triangle?

[hint =area of triangle=
1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}
​

Answer 1

Step-by-step explanation:

hope it helps

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Answer 2

Answer:

area of triangle=1/2{a(-a-√3)-a(√3-a)-√3a(a+a)}

=1/2{-a^2-√3a-√3a+a^2-2√3a^2}

=1/2{-2√3a-2√3a^2}

=√3a(-1-a) sq unit.