Question

find the area of triangle two side of which 18cm and 10cm and the perimeter is 42cm​

Answer 1

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Answer 2

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Two sides of the triangle = 18cm and 10cm

Perimeter of the triangle = 42cm

Third side of triangle = 42 - (18+10) cm = 14cm

Semi perimeter of triangle = 42/2 = 21cm

Using heron's formula,

Area of the triangle = √s (s-a) (s-b) (s-c)

= √21(21 - 18) (21 - 10)

21 - 14) cm2

= √21 × 3 × 11 × 7 m2

= 21√11 cm2 .