find the area of triangle two side of which are 8 cm and 11cm and the perimeter is 32 Cm
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Given ,
- the two side of triangles are 8cm and 11cm
- The perimeter of the triangle is 32cm .
To find ,
- The area of the triangle
Here ,
- p = 32cm
- side a = 8cm
- side b = 11cm
To find the side "c" = 32cm - (8+11)cm = 13cm .
So, side c is 13cm .
Now ,
2s = 32
=> s = 32/2
=> s =>16
So ,
- s-a = (16-8) = 8cm
- s-b =(16-11) = 5cm
- s-c = (16-13) =3cm
Therefore ,
Area the triangle = √s(s-a)(s-b)(s-c)
Area of the triangle = √16×8×5×3 cm^2
Area of the triangel = 8√30cm^2
The area of the Triangle is 8√30cm^2 .
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