Math, asked by dishagoyal50281, 9 months ago

Find the area of triangle two sides of which 14 cm and 11 cm and the perimeter is 42 cm​

Answers

Answered by parasbhumbak3
2

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Answered by durbasmritisaha9734
2

Answer:

1ST SIDE = 14Cm

2nd side = 11 cm

3 rd side = 42 - ( 14+ 11)

= 42 - 25

=17cm

area of triangle = √ s ( s- a) ( s-b) ( s-c)

where , s = a + b+ c / 2

a= 1st side

b= 2nd side

c= 3rd side

s= 14+ 11+ 17/ 2

= 21

√ 21× 7 × 10 × 4

√ 7×3× 7× 5× 2 × 2× 2

7 × 2 √ 3× 5 × 2

14 √ 30 cm2 ans.

the calculation maybe wrong.

check it............ok

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