Find the area of triangle two sides of which are 18 cm and 10cm and the perimeter is 42 cm ⇔
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Answered by
1
Answer
Area of triangle
s(s−a)(9−b)(s−0)
Here, s is the semi- perimeter,
and a,b,c are the sides of the triangle
Given a=18 cm, b=10 cm
and perimeter =42 cm
semi- perimeters=
2
perimeter
=
2
42
s=21cm.
Area of triangle
∴c=42−(18+10)cm =14 cm
∴ Area of triangle=
21.(21−18)(21−10)(21−14)
=
21.3.7.11
cm
2
=
3×7×3×7×11
cm
2
=
(3×7)
2
×11
cm
2
=21
11
cm
2
∴ Thus, the required area of the triangle is
21
11
cm
2
Answered by
0
Answer:
a+b+c=42
18+10+c=42
c=28
now,finding area of triangle
applying herons formula
18+10+14/2=21
✓21(21-18) (21-10)(21-14
✓21×✓3×✓11×✓7
=3×7×3×11×7
=21✓11
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