Find the area of triangle two sides of which are 18cm and 10 cm and the perimeter is 42cm
Answers
Answered by
2
Step-by-step explanation:
First side :18
Second side:10
Let the third side be :x
A.T.O
18+10+x=42
28+x=42
x=1 5 ANS
Answered by
1
A=15
1 st is 18 cm
2 nd is 10 cm
3 rd is A
Perimeter is 42cm
So 18+10+A=42 cm
28+A =42
So,42-28= 15 cm there fore A=15 cm
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1 st is 18 cm
2 nd is 10 cm
3 rd is A
Perimeter is 42cm
So 18+10+A=42 cm
28+A =42
So,42-28= 15 cm there fore A=15 cm
Please mark me as brainlist
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