Math, asked by ujagar6875, 1 year ago

Find the area of triangle two sides of which are 8 cm and 11 cm and the perimeter is 32 CM use 5.48

Answers

Answered by brainly52
0
let a = 8cm , b = 11cm c = ?
given,      perimeter,P = 32cm
this gives.                P = a + b+ c = 32
                                c = P - (a+ b) = 32 - (8 + 11)
                                   = 32 - 19
                                   = 13cm

now,   semi-perimeter,S = P/2 = 32/2 = 16cm

Using Heron's formula,  Area,A = sq root{S(S - a)(S- b)(S- c)}
                                                  = sq root{16(16 - 8)(16 - 11)(16 - 13)}
                                                  = sq root{16(8)(5)(3)}
                                                  = sq root(1920)
                                                  = 43.82 cm^2
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