Math, asked by knowledge41111, 6 months ago

Find the area of triangle ,two sides of which are 8 cm and 11 cm and the perimeter is 32 cm ​

Answers

Answered by email2tarin
1

Step-by-step explanation:

Triangle

Solve for area

A≈43.82cm²

a Side

8

cm

b Base

11

cm

P Perimeter

32

cm

γ

c

a

h

b

b

h

b

h

b

c

γ

a

b

a

c

b

γ

P

c

γ

a

b

A

Answered by Anonymous
2

Step-by-step explanation:

using herons formula

√(s (s-a)(s-b)(s-c))

S= Perimeter/2

S=32/2=16

a=8,b=ll, c = x

C=a+b-32

C = 8+II-32

C=13

Area of ∆is = √(16 (16-8) (16-11) (16-13))

= √(16 (8) (5) (3)

= 8√30

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