Question

Find the area of triangle ,two sides of which are 8 cm and 11 cm and the perimeter is 32 cm ​

Answer 1

Answer:

your required answer is this

I hope it will help you

Answer 2

$\underline\mathfrak\blue{ᴀɴsᴡᴇʀ:—}$

Here we have perimeter of the triangle = 32 cm, a = 8 cm and b = 11 cm.

Third side c = 32 cm - (8 + 11)cm = 13 cm

.

So, 2s = 32, i.e., s = 16 cm,

s - a = (16 - 8) cm = 8 cm,

s - b = (16 - 11) cm = 5 cm,

s - c = (16 - 13) cm = 3 cm.

.

Therefore, area of the triangle

$= \sqrt{s(s - a)(s - a)(s - c)}$

$= \sqrt{16×8×5×3}cm² \:=\:8 \sqrt{30}\:cm²$