Question

Find the area of triangle two sides of which are 8 cm and 11cm and the perimeter is 32cm

Answer 1

Answer:

Step-by-step explanation:

PERIMETER = 32 => SIDE +SIDE+SIDE

FIRST SIDE = 8

SECOND SIDE = 11

THIRD SIDE = 32-11+8=>32-19

                                     =13

AREA OF TRIANGLE= PUT THE VALUES IN HERONS FORMULA

Answer 2

Answer:

Given:-

Side a = 8 cm

Side b = 11 cm

Side c = ???

Perimeter = 32 cm

To Find:-

Area of triangle

Solution:-

To find the area, we have to firstly find the all sides of triangle.

so, we know that

⇒ a + b + c = 32 cm

⇒ 8 + 11 + c = 32 cm

⇒ 19 + c = 32

⇒ c = 32 - 19

⇒ c = 13 cm

Area of triangle = √ (s (s-a) (s-b) (s-c) )

Here s is the semi-perimeter.

Semi-perimeter = Perimeter/2 = 32/2= 16 cm

Putting all the values, we get

⇒ √ (s (s-a) (s-b) (s-c) )

⇒ √(16 × (16−8) × ( 16−11) × (16−13))

⇒ √ (16 × 8 × 5 × 3)

⇒ √8 × 2 × 8 × 5 × 3

⇒ √8 × 8 × 2 × 5 × 3

⇒ 8 √ 2 × 5 × 3

= 8√30 cm²

Hence, Area of triangle is 8√30 cm².