find the area of triangle two sides of which are18 cm and10 cm and the perimeter is42 cm
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perimeter=42
third side=42-(18+10)
third side=14cm
s=(a+b+c)/2
(18+10+14)/2
42/2=21
area =rootover s(s-a)(s-b) (s-c)
=root over 21(21-18)(21-10)(21-14)
=root over21(3)(11)(7)
root over4851
69.65cm
third side=42-(18+10)
third side=14cm
s=(a+b+c)/2
(18+10+14)/2
42/2=21
area =rootover s(s-a)(s-b) (s-c)
=root over 21(21-18)(21-10)(21-14)
=root over21(3)(11)(7)
root over4851
69.65cm
kumu89:
sorry this is woring answer
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