Find the area of triangle two sides of which re 18 cm and 10 cm and the perimeter is 42 cm .
Answers
Answered by
8
well friend
you can get your answer in he given attachment
you can get your answer in he given attachment
Attachments:
Anonymous:
gr8!
Answered by
7
Perimeter of triangle=a+b+c=42cm
=> 18+10+c=42cm
=>28+c=42cm
=>c= (42-28)cm
=>c=14cm
s =42/2
=21cm
s-a =21-18
=3cm
s-b=21-10
=11cm
s-c=21-14
=7cm
area of triangle= √s(s-a)(s-b)(s-c)
√21×3×11×7
√3×7×3×11×7
3 ×7√11
21√11 cm
or
69. 6436cm (approx)
I HOPE IT WILL HELP YOU
=> 18+10+c=42cm
=>28+c=42cm
=>c= (42-28)cm
=>c=14cm
s =42/2
=21cm
s-a =21-18
=3cm
s-b=21-10
=11cm
s-c=21-14
=7cm
area of triangle= √s(s-a)(s-b)(s-c)
√21×3×11×7
√3×7×3×11×7
3 ×7√11
21√11 cm
or
69. 6436cm (approx)
I HOPE IT WILL HELP YOU
Similar questions