Math, asked by f191shivam, 11 months ago

FIND THE AREA OF TRIANGLE , TWO SIDES WHICH ARE 8 CM AND 11 CM AND IT,S PERIMETER IS 132 CM

PLEASE HELP ME TO GET OUT OF THIS PROBLEM

Answers

Answered by reshmasri246
0

Answer:

Step-by-step explanation:

8+11=132

19/132

by using herons formulas

s√s(s-a)(s-b)(s-c)

Answered by bhavikachopra50
0

Let me help u out

Side 1+side 2+side 3=perimeter

8+11+side 3=132cm

19+ side 3=132 cm

Side 3=132-19=113

Therefore, the other side is 113 cm

Area=1/2*b*h=1/2*8*11=44 cm se

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