Math, asked by amigaming2580, 8 months ago

find the area of triangle,two sides which are 8cm,11cm and the perimeters is 32 cm​

Answers

Answered by harshapedakota6
1

Step-by-step explanation:

let consider sides of triangles 8,11,x respectively.

perimeter of triangle 32 cm.

perimeter = a +b+c (where a,b,c are sides of triangle)

8+11+x=32

19+x=32

x=13 cm

Answered by Vaanchhit
0

Answer:

8√30 cms

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Step-by-step explanation:

Third side is = 32 - (8 + 11) = 32 - 19 = 13 cm

AREA =

√ s( s- a) ( s- b) s- c) where a,b and c are the sides of triangle

= 16 (16-8)(16-11)(16-13)

=√ 16 × 8×5× 3

=√ 128× 5×3

=√ 640× 3

=√ 1920

=  8√30

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