find the area of triangle,two sides which are 8cm,11cm and the perimeters is 32 cm
Answers
Answered by
1
Step-by-step explanation:
let consider sides of triangles 8,11,x respectively.
perimeter of triangle 32 cm.
perimeter = a +b+c (where a,b,c are sides of triangle)
8+11+x=32
19+x=32
x=13 cm
Answered by
0
Answer:
8√30 cms
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Step-by-step explanation:
Third side is = 32 - (8 + 11) = 32 - 19 = 13 cm
AREA =
√ s( s- a) ( s- b) s- c) where a,b and c are the sides of triangle
= 16 (16-8)(16-11)(16-13)
=√ 16 × 8×5× 3
=√ 128× 5×3
=√ 640× 3
=√ 1920
= 8√30
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