Question

Find the area of triangle using Heron's formula the sides are 8cm,6cm,10cm,

Answer 1

s=a+b+c/2
s=8+6+10/2
s=12
area=√s(s-a)(s-b)(s-c)
=√12*(12-8)(12-6)(12-10)
=√12*4*6*2
=√24*24
=24cm^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=24\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle = 8 cm,6 cm,10 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{8+ 6+ 10}{2} \\ \\ : \implies s = \frac{24}{2} \\ \\ \green{ : \implies s = 12} \\ \\ \circ\: \bold{area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{12(12 - 8)(12-6)(12 - 10)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{12 \times 4 \times 6\times 2} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{576} \\ \\ : \implies \text{Area \: of \: triangle =}24 \: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle = 24 {cm}}^{2} }$