Question

Find the area of triangle whase sides are
: 10 cm, 24 cm, 26 cm.​

Answer 1

Answer:

Triangle

Solve for area

A=hbb

2

b Base

10

cm

hb Height

Enter value

cm

Step-by-step explanation:

flw pls

Answer 2

Answer:

120 cm²

Step-by-step explanation:

Given -

Sides of triangle = 10 cm, 24 cm, 26 cm

To find -

The area of triangle

Solution -

Area of triangle =

$\sqrt{s( s-a )( s- b)( s-c )}$

Where s = semi perimeter

a, b, c = sides of triangle

We have (a, b, c) we have to find semi perimeter

s = (a + b + c)/2

= (10+24+26)/2

= 60/2

= 30 cm

Area =

$\sqrt{s( s- a)( s-b ) ( s-c )} \\ = \sqrt{30 \times (30 - 10) \times (30 - 24) \times (30 - 26)} \\ = \sqrt{30 \times 20 \times 6 \times 4} \\ = \sqrt{10 \times 3 \times 10 \times 2 \times 2 \times 3 \times 2 \times 2} \\ = \sqrt{ {10}^{2} \times {2}^{2} \times {2}^{2} \times {3}^{2} } \\ = 10 \times 2 \times 2 \times3 \\ = 120 {cm}^{2}$

Hence area = 120 cm²

hope it helps.