Question

find the area of triangle whase vertices are [2;3] [-1;0] [2;-4]​

Answer 1

Answer:

The area of the triangle is 10.5 sq. unit

Step-by-step explanation:

In the context to the question;

we have to find the area of the triangle by using the vertices provided;

given;

[2;3] [-1;0] [2;-4]​

Now we know that ;

Area of triangle = 1/2 [ x₁(y₂-y₃)+ x₂(y₃-y₁)+ x₃(y₁-y₂)]

here we know;

(x₁,y₁)=[2;3]

(x₂,y₂)= [-1;0]

(x₃,y₃)= [2;-4]​

now by putting the value in the formula;

Area of triangle = 1/2 [ 2(0+4 )+ (-1)(4-3)+ 2(3-0)]

= 1/2 [ 2 (4) -1(-7)+2(3)]

=1/2 [[ 8+7+6 ]

=1/2[ 21 ]

now by dividing 21 by 2;

=10.5 sq. unit

so the area of the triangle is 10.5 sq. unit