Find the area of triangle which two sides in cm and 10 cm and the perimeter is 42 cm
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Answer:
A= two sides given as
= 10m
soo 2× 10m= 20m
perimeter- 42
now subtract 42-20m=22
now using herons formula find the area=
a=10
b=10
c=22
a+b+c by
2
= 10+10+22 = 42÷2 = 21
2
21-10=11
21-10=11
21-22=1
21×11×11×1
3×7×11×11
121√21
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