Math, asked by shakher567, 1 year ago

find the area of triangle who sides are 11m ,60m and 61m

Answers

Answered by shiva3618
0
Area= 2* given meter
=2*11= 22.

Area=2* given meter
=2*60= 120.

Area= 2* given meter
=2*61= 122.

Hope my answer will be helpful to u plz... mark as brainliest.

shiva3618: plz.. mark as brainlist
Answered by CKS
0
here

semi perimeter is 132/2 = 66 m

by using herons formula we have

area = sqrt [66 (66 - 11) (66 - 60) (66 - 61)]
= sqrt ( 66 × 55 × 6 × 5)
= sqrt (11 × 6 × 11 × 5 × 6 × 5)
= 11 × 6 × 5
= 330 m^2

hope it helps

shakher567: sqrt kya h
shiva3618: 22sq, 66 sq, 120sq.
CKS: it square root
shiva3618: 1). 22 2). 120 3). 122.
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