find the area of triangle who sides are 11m ,60m and 61m
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Answered by
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Area= 2* given meter
=2*11= 22.
Area=2* given meter
=2*60= 120.
Area= 2* given meter
=2*61= 122.
Hope my answer will be helpful to u plz... mark as brainliest.
=2*11= 22.
Area=2* given meter
=2*60= 120.
Area= 2* given meter
=2*61= 122.
Hope my answer will be helpful to u plz... mark as brainliest.
shiva3618:
plz.. mark as brainlist
Answered by
0
here
semi perimeter is 132/2 = 66 m
by using herons formula we have
area = sqrt [66 (66 - 11) (66 - 60) (66 - 61)]
= sqrt ( 66 × 55 × 6 × 5)
= sqrt (11 × 6 × 11 × 5 × 6 × 5)
= 11 × 6 × 5
= 330 m^2
hope it helps
semi perimeter is 132/2 = 66 m
by using herons formula we have
area = sqrt [66 (66 - 11) (66 - 60) (66 - 61)]
= sqrt ( 66 × 55 × 6 × 5)
= sqrt (11 × 6 × 11 × 5 × 6 × 5)
= 11 × 6 × 5
= 330 m^2
hope it helps
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