Question

find the area of triangle whole side are Aom 32m and 24m
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Answer 1

Correct Question:

• Find the area of triangle whose side is 40m , 32m and 24m

Answer :

• Area of triangle = 384m²

Given :

• Area of triangle whose sides are 40m , 32m and 24m.

To find :

• Area of triangle

Solution :

Given ,

Sides of triangle

• A = 40m
• B = 32m
• c = 24m

As we know that ,

• Area = √s(s - a) (s - b) (s - c)

where, s = a+b+c/2

Now Putting the value ,

⇢ s = a+b+c /2

⇢ s = 40 + 32 + 24/ 2

⇢ s = 48

Now ,

• Area = √s(s - a) (s - b) (s - c)

⇢ Area = √48(48 - 40) (48 - 32) (48 - 24)

⇢ √48 × 24 × 8 × 16

⇢ 384m²

Hence , The area of triangle is 384m²

Answer 2

Given:-

Side of triangle

• A = 40m
• B = 32m
• C =24m

We know that,

$\Large\sf\purple{Area=√s(s-a)(s-b)(s-c)}$

where, $\large\sf\red{S={\frac{a+b+c}{2}}}$

Now putting the value,

$\large\sf\red{S={\frac{a+b+c}{2}}}$

$\sf \implies \: s = \frac{40 + 32 + 24}{2} \\ \\ \sf \implies \: s = 48$

Hence, SemiPerimeter of a triangle is 48.

Now,

$\Large\sf\purple{Area=√s(s-a)(s-b)(s-c)}$

$\sf \implies \: area = \sqrt{48(48 - 40)(48 - 32)(48 - 24)} \\ \\ \sf \implies \: \sqrt{48 \times 24 \times 8 \times 16} \\ \\ \sf \implies \: 384 {m}^{2}$

Hence, Area of triangle is 384$\sf{m}^{2}$