Question

find the area of triangle whose are 14 24 and 32 and also find altitude on smallest side of triangle ​

Answer 1

Answer:

S= 14+24+32/2 = 70/2 = 35

Area =√s(s-a)(s-b)(s-c)

= √35(35-14)(35-24)(35-32)

= √35*21*11*3

= √7*5*7*3*11*3

= 7*3*5*11

= 21√55 square unit

Now, Area=1/2*b*h

21√55= 1/2*14*h

21√55/7 = h

h = 3√55

• Hope this helps you